My daughter has an older Seiko Westminster/Whittington wall clock with the markings “QXD102BC SMRW”. It operates with 4 AA batteries. The battery holder and mechanism form one case – one battery left followed by the mechanism, then three batteries on the right. I’ve tried many avenues to find a replacement mechanism to no avail. It was one of her wedding presents.
Quick search shows me this one: https://www.amazon.com/Seiko-Clock-Movement-Westminster-Whittington/dp/B00NGYSYVE I know, not the same number, but you might have to retrofit something to make it work.
Here's another possible source: Timesavers I wouldn't worry so much about it having to contain the batteries. You could probably work around that part.
Don't know how familiar you are with the mechanism you suggest. Looks like I can work with it. If I'm correct, the holder for the speaker on that unit can be removed (I need the space). I would use the speaker that comes with the replacement, but I'm not sure it will fit in the separate compartment this clock has for the speaker. In order to get at this compartment it appears that I must remove the face and I'm not sure how it attaches. The hands are off and shaft and mechanism removed. The decorative rim around the face can be lifted slightly at some points. I'm afraid of breaking it. Another option I thought of was to merely splice the wires reusing the existing speaker, but I'm not sure if the speakers (new and old) are compatible. Would appreciate your input.
I am not familiar with this particular clock. But, after you remove the hands and the nut that holds the movement, it is most likely held in place by some rubber spacers and glue pads. Unless you see some screws mounted from the back.
Absolutely correct. Managed to get front and back off the mounting board. Looks like doubleback tape. Speaker is same size and on the one you suggest. Looked on eBay and there are a few of the same mechanisms, one with a shorter shaft which would work to my advantage. Will order one today. So I think you've solved my problem. Thanks so much for your help.