devils4ever
Registered User
- Mar 28, 2014
- 64
- 1
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I'm in the process of designing a clock and I'm having trouble understanding the way the hour hand is concentric with the minute hand. Plus, I'd like someone to check my overall calculations. I'm using "Making Clocks" by Stan Bray as a reference. See below.
Great wheel is 96T, center wheel is 96T, third wheel is 90T. All pinions as 12T. The escapement wheel has 30T with a 39.14" long pendulum giving a 2 second period . So, the escapement wheel turns once per minute. The third wheel rotates at 90:12 = 7.5:1 ratio or 60 sec * 7.5 = 450 sec/rev. The center wheel rotates at 96:12 = 8:1 ratio = 450 sec/rev * 8 = 3600 sec/rev (once per hour). Finally, the great wheel rotates at 96:12 = 8:1 ratio = 3600 sec/rev * 8 = 28,800 sec/rev or 8 hrs/rev.
I think I got this part correct, but tell me if I'm wrong. All these wheels and pinions are vertical in the pic below.
Now, I'm not sure how to get the hour hand connected to this. I need to reduce the minute hand on the center wheel by a factor of 12. So, I'm thinking of using a 48:12 ratio and a 36:1 ratio to get this. The wheel on the right is 48T and mates with a 12T pinion on the center wheel. This wheel has a 12T pinion and mates with the 36T wheel. This gives the proper rate and direction of rotation, but obviously the bore in this wheel doesn't line up with the center wheel's bore because the 48T wheel has a difference pitch diameter than the 36T wheel.
How does this get resolved?
Thanks!
Great wheel is 96T, center wheel is 96T, third wheel is 90T. All pinions as 12T. The escapement wheel has 30T with a 39.14" long pendulum giving a 2 second period . So, the escapement wheel turns once per minute. The third wheel rotates at 90:12 = 7.5:1 ratio or 60 sec * 7.5 = 450 sec/rev. The center wheel rotates at 96:12 = 8:1 ratio = 450 sec/rev * 8 = 3600 sec/rev (once per hour). Finally, the great wheel rotates at 96:12 = 8:1 ratio = 3600 sec/rev * 8 = 28,800 sec/rev or 8 hrs/rev.
I think I got this part correct, but tell me if I'm wrong. All these wheels and pinions are vertical in the pic below.
Now, I'm not sure how to get the hour hand connected to this. I need to reduce the minute hand on the center wheel by a factor of 12. So, I'm thinking of using a 48:12 ratio and a 36:1 ratio to get this. The wheel on the right is 48T and mates with a 12T pinion on the center wheel. This wheel has a 12T pinion and mates with the 36T wheel. This gives the proper rate and direction of rotation, but obviously the bore in this wheel doesn't line up with the center wheel's bore because the 48T wheel has a difference pitch diameter than the 36T wheel.
How does this get resolved?
Thanks!